Jawab:
trigonometri
Penjelasan dengan langkah-langkah:
tan θ = - 8/15 dan cos θ > 0 maka θ dikuadran IV
.
tan θ = -8/15 = - (y/x)
r² = x² +y²
r² = 64 + 225 = 289
r = √289 = 17
sin θ = - y/r = -8/17
cos θ = x/r = 15/17
a) sin θ cos θ + cos θ sin θ =
= 2 sin θ cos θ
= 2(-8/17)(15/17)
= - 240 /289
b) csc θ= (1/sin θ) = -17/8
cot θ = 1/ tan θ = - 15/8
csc θ / cot θ = - 17/8 / ( -15/8)
= -17/8 x - 8/15
= 17/15
semoga dpt membantu..
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Verified answer
Jawab:
trigonometri
Penjelasan dengan langkah-langkah:
tan θ = - 8/15 dan cos θ > 0 maka θ dikuadran IV
.
tan θ = -8/15 = - (y/x)
r² = x² +y²
r² = 64 + 225 = 289
r = √289 = 17
sin θ = - y/r = -8/17
cos θ = x/r = 15/17
a) sin θ cos θ + cos θ sin θ =
= 2 sin θ cos θ
= 2(-8/17)(15/17)
= - 240 /289
b) csc θ= (1/sin θ) = -17/8
cot θ = 1/ tan θ = - 15/8
csc θ / cot θ = - 17/8 / ( -15/8)
= -17/8 x - 8/15
= 17/15
semoga dpt membantu..