" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Recordemos : (a+b)² = a² + 2ab + b²
(2X+3Y)² = (2X)² + 2(2X)(3Y) + (3Y)²
= 4X² + 12XY + 9Y² ---> Verdadero
b) (2a - 1)(2a + 1) = 4a2 - 2
Aplicamos propiedad distributiva
4a² + 2a - 2a - 1 2a - 2a = 0
Quedaría : 4a² - 1 ---> Falso
c) (x - 1)3 = x3 - 3x2 + 3x -1
Recordemos : (a-b)³ = a³ - 3a²b + 3ab² - b³
(X-1)³ = (X)³ - 3(X)²(1) + 3(X)(1)² - (1)³
X³ - 3X² + 3X - 1 ---> Verdadero
Saludos desde Venezuela