" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
entonce limx->1(tan(x-1))/(x-1)=1
limx->1(tan(x-1))/(x^2-1)(x^2-4x+3)=limx->1(tan(x-1))/(x-1)(x+1)(x^2-4x+3)=
limx->1(tan(x-1))/(x-1)*limx->1 1/(x+1)(x^2-4x+3)=1*1/(1+1)(1^2-4*1+3)=
=1*1/2*0=1*1/0=1/0=+infinito