Oblicz masę ZnSO4 która wykrystalizuje z 80g 2-molowego roztworu tej soli o gęstości 1.12 g/cm(szescienne)
d=1,12g/cm3
m=80g
v=m/d
v=80/1,12
v = 71,43cm3 = 0,0714dm3
v=0,0714dm3
Cm=2mol/dm3
n=Cm*v
n=2*0,0714
n = 0,143mola
M ZnSO4= 161g/mol
n=0,143mola
m=n*M
m=0,143*161
m = 23,02g
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d=1,12g/cm3
m=80g
v=m/d
v=80/1,12
v = 71,43cm3 = 0,0714dm3
v=0,0714dm3
Cm=2mol/dm3
n=Cm*v
n=2*0,0714
n = 0,143mola
M ZnSO4= 161g/mol
n=0,143mola
m=n*M
m=0,143*161
m = 23,02g