Oblicz ile gramów wodorotlenku sodu znajduje się w 50cm³ roztworu o stężeniu 20% i gęstości 1,275 g/cm³.
v=50cm3
d=1,275g/cm3
m=?
m=v*d
m=50*1,275
m = 63,75g
mr=63,75g
Cp=20%
ms=?
Cp=ms*100%/mr
ms=Cp*mr/100%
ms=20*63,75/100
ms = 12,75g NaOH
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v=50cm3
d=1,275g/cm3
m=?
m=v*d
m=50*1,275
m = 63,75g
mr=63,75g
Cp=20%
ms=?
Cp=ms*100%/mr
ms=Cp*mr/100%
ms=20*63,75/100
ms = 12,75g NaOH