Ile gramów siarczanu (IV) glinu znajduje się w 300 cm³ roztworu 18%? Gęstość tego roztworu wynosi 1,2 g/cm³.
v=300cm3
d=1,2g/cm3
m=v*d
m=300*1,2
m = 360g
mr=360g
Cp=18%
ms=Cp*mr/100%
ms=18*360/100
ms = 64,8g
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v=300cm3
d=1,2g/cm3
m=v*d
m=300*1,2
m = 360g
mr=360g
Cp=18%
ms=Cp*mr/100%
ms=18*360/100
ms = 64,8g