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r = 15:2 = 7,5 mm = 0,75 cm
Pp = π0,75²
Pp = 0,5625π cm²
V = Pp * H
V = 0,5625π * 0,4 = 0,225πcm³
dm - gęstość miedzi
dm= 8,9 g/cm³
m= dm * V
m = 8,9 * 0,225π = 2,0025 g
Odpowiedź: Masa rurki wynosi 2,0025 g