oblicz stężenie molowe 20-procentowego roztworu NaOH o gęstości d=1,219 g/cm3
DAJĘ NAJ
cp=20%
d=1,219g/cm3=1219g/dm3
Mm=40 g/mol
Cm= (cp*dr)/100Mm= (20%*1219 g/dm3)/100*40 g/mol= 6,096mol/dm3
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cp=20%
d=1,219g/cm3=1219g/dm3
Mm=40 g/mol
Cm= (cp*dr)/100Mm= (20%*1219 g/dm3)/100*40 g/mol= 6,096mol/dm3