oblicz stężenie molowe 30% roztworu HNO3 o gęstości 1,18g/cm3
Cp=30%
M HNO3=63g/mol
d=1,18g/cm3=1180g/dm3
Cm=?
Cm=Cp*d/M*100%
Cm = 30*1180/63*100
Cm = 5,62mol/dm3
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Cp=30%
M HNO3=63g/mol
d=1,18g/cm3=1180g/dm3
Cm=?
Cm=Cp*d/M*100%
Cm = 30*1180/63*100
Cm = 5,62mol/dm3