oblicz ile gramów chlorku glinu znajduje sie w 0.4 dm3 roztworu o stężeniu 10 % jezeli jego gęstosc wynosi 1,09 g/cm3
V = 0,4dm³ = 400cm³
d = 1,09g/cm³
m = dV
m = 1,09g/cm³ x 400cm³ = 436g
ms = mr x cp/100%
ms = 436g x 10%/100% = 43,6g
Pozdrawiam Marco12 ;)
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V = 0,4dm³ = 400cm³
d = 1,09g/cm³
m = dV
m = 1,09g/cm³ x 400cm³ = 436g
ms = mr x cp/100%
ms = 436g x 10%/100% = 43,6g
Pozdrawiam Marco12 ;)