ile gramów siarczku sodu znajduje sie w 0,5 dm3 roztworu 8% o gęstości 1,09g/cm3?
DANE:
V=0,5dm3= 500cm3
Cp= 8%
d= 1,09g/cm3
WZOR
d=m/v
m= v*d
m= 500cm3 * 1,09g/cm3=545g masa roztworu
Cp=ms*100%/mr
ms=Cp* mr/100%
ms= 8%* 545g/ 100%= 43,6g
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DANE:
V=0,5dm3= 500cm3
Cp= 8%
d= 1,09g/cm3
WZOR
d=m/v
m= v*d
m= 500cm3 * 1,09g/cm3=545g masa roztworu
Cp=ms*100%/mr
ms=Cp* mr/100%
ms= 8%* 545g/ 100%= 43,6g