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v=50cm3
d=m/v
m=v*d
m=50*1,2
m=60g
Z def.stęż.procent.
18g------100g roztworu
xg--------60g roztworu
x=60*18/100
x=10,8g NaOH
mNaOH=40u
NaOH + HBr------>NaBr + H2O
40g NaOH-------22,4dm3 HBr
10,8g NaoH-------xdm3 HBr
x=10,8*22,4/10,8
x=6,05dm3 HBr
Należy użyć 6,05dm3 bromowodoru