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V alkoholu= 250 cm3
d alk.= 0,79g/cm3
m(I)=6,2 g
Cp=?
d=m/V
m=d*V
m=197,5 g
Cp=ms*100%/mr
ms=6,2g
mr=6,2+197,5=203,7g
Cp=6,2*100%/203,7
Cp=3,04%
Odp. Uzyskano ;]