oblicz, liczbę moli azotu, zawartą w 10 dm3 tego gazu, odmierzonego w temperaturze 400stopniC i pod ciśnieniem 1000hPa
V=10dm3=0,01m3
T=400stC=673st K
P=1000hPa=100 000 Pa
R= 8,31 j/mol*K
n=?
pV=nRT
n=pV/RT
n=100000*0,01/8,31*673
n=1000/5593
n=0,18 mola N2
V=10dm³
T=673K
p=1000hPa
R=83,1 dm³*hPa/mol*K
pV=nRT /:RT
n=1000[hPa]*10[dm³] / 83,1dm³*hPa/mol*K * 673K
n=0,2mol
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V=10dm3=0,01m3
T=400stC=673st K
P=1000hPa=100 000 Pa
R= 8,31 j/mol*K
n=?
pV=nRT
n=pV/RT
n=100000*0,01/8,31*673
n=1000/5593
n=0,18 mola N2
V=10dm³
T=673K
p=1000hPa
R=83,1 dm³*hPa/mol*K
n=?
pV=nRT /:RT
n=pV/RT
n=1000[hPa]*10[dm³] / 83,1dm³*hPa/mol*K * 673K
n=0,2mol