Ile gramów tlenku krzemu potrzeba do reakcji z 100cm3 20% roztworu NaOH o gestosci 1,4g/cm3 aby otrzymać krzemian sodu? Odp. 17,64g Bardzo proszę o pomoc
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Cp=20%
V=100cm^3
100cm^3-----x[g]
1cm^3-------1,4g
x=140g ->mr
Cp=ms*100%/mr
20%=ms*100%/140g
ms=28gNaOH
SiO2+ 2NaOH----> Na2SiO3 + H2O
60g---80g
x[g]---28g
x=21g