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V=0,5 dm3
ms= 9,8
I obli ilosc moli H2SO4
1mol - 98 g
x - 9,8
x= 0,1
II Cmol
Cmol = ns/v
Cmol= 0,1/0,5 = 0,2
2.
V=0,4dm
Cmol=5
ns= 0,4 x 5 = 2mole
1 mol=106 g
2mole - 212g
3.
Cmol=6,3
d=1,2g/cm3= 1200g/dm3
M=63
Cp= Cmol(100M)/d
Cp= 6,3 (6300)/1200
cP= 33 %