CIĄGI ARYTMETYCZNE:
1. 3 , x , y, 33
2.
a13=?
3. 3 , 8 , 13 , ...
S31
zadanie 1
Z własności ciągu arytmetycznego
x = 0,5(3+y)
y = 0,5(x+33)
y = 0,5[0,5(3+y) + 33] = 0,5(1,5 + 0,5y + 33) = 0,25y + 17,25
y = 0,25y + 17,25
0,75y = 17,25
y = 23
x = 0,5(3+23) = 0,5*26 = 13
x = 13
zadanie 2
a₄ = a₁ + 3r = 11
a₈ = a₁ + 7r = 35
a₁ + 3r = 11
a₁ + 7r = 35
-----------------
4r = 24
r = 6
a₁ + 3*6 = 11
a₁ + 18 = 11
a₁ = -7
a₁ = -7 i r = 6
a₁₃ = a₁ + 12r
a₁₃ = -7 + 12*6 = 65
zadanie 3
a₁ = 3
a₂ = 8
a₃ = 13
r = a₂ - a₁
r = 8 - 3 = 5
a₃₁ = a₁ + 30r
a₃₁ = 3 + 30*5 = 153
S₃₁ = 0,5(3+153) x 31 = 2418
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
zadanie 1
Z własności ciągu arytmetycznego
x = 0,5(3+y)
y = 0,5(x+33)
y = 0,5[0,5(3+y) + 33] = 0,5(1,5 + 0,5y + 33) = 0,25y + 17,25
y = 0,25y + 17,25
0,75y = 17,25
y = 23
x = 0,5(3+23) = 0,5*26 = 13
x = 13
y = 23
zadanie 2
a₄ = a₁ + 3r = 11
a₈ = a₁ + 7r = 35
a₁ + 3r = 11
a₁ + 7r = 35
-----------------
4r = 24
r = 6
a₁ + 3*6 = 11
a₁ + 18 = 11
a₁ = -7
a₁ = -7 i r = 6
a₁₃ = a₁ + 12r
a₁₃ = -7 + 12*6 = 65
zadanie 3
a₁ = 3
a₂ = 8
a₃ = 13
r = a₂ - a₁
r = 8 - 3 = 5
a₃₁ = a₁ + 30r
a₃₁ = 3 + 30*5 = 153
S₃₁ = 0,5(3+153) x 31 = 2418
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)