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H = 0,7 m
D(średnica) = 5 m
r = D/2 = 2,5 m
(π =3,14 )
V = πr² × H
V = 3,14 × (2,5²) × 0,7
V = 2,198 × 6,25
V = 13,7375 m³
1m³ = 3,5 zł
13,7375 m³ = x
x = 13,7375 × 3,5
x = 48,08125 ≈ 48,08 zł
Odp. 48,08 zł kosztuje napełnienie tego basenu