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l₀= 40 cm= 0,4 m
t₁= 20°C
t₂= 70°C
Δt= t₂-t₁
Δt= 50°C
α=2×10⁻⁵/°C
Dit= lt
Jwb=
lt= l₀.(1+α.Δt)
lt=0,4.(1+2×10⁻⁵.50)
lt= 0,4.(1+1×10⁻³)
lt=0,4+ 4×10⁻⁴
lt=0,4004 m
lt= 40,04 cm