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f(1) = 1.0
= 0
f(2)= 2.11
= 22
f(-2) = 2.3
= 6
f(x) = 1:x
(1,0)-> 0= a(1)^2 + b(1) + c
0= a+b+c
(2,11) -> 11= a(2)^2 + b(2) + c
11= 4a + 2b+c
(-2,3) -> 3=a(-2)^2 + b(-2) + c
3= 4a - 2b + c
Eliminasi, subtitusi,
dapet:
a=3
b=2
c=-5
Fungsi kuadrat: f(x)=3x^2 + 2x - 5