Question

Carilah fungsi kuadrat yang melalui tititk- titik (1,0) (2,11) Dan (-2,3)

Answer 1

F(x)
f(1) = 1.0
= 0
f(2)= 2.11
= 22
f(-2) = 2.3
= 6
f(x) = 1:x

Answer 2

Pake rumus y=ax^2 + bx+c

(1,0)-> 0= a(1)^2 + b(1) + c
             0= a+b+c 
(2,11) -> 11= a(2)^2 + b(2) + c
              11= 4a + 2b+c
(-2,3) -> 3=a(-2)^2 + b(-2) + c
            3= 4a - 2b + c
Eliminasi, subtitusi,
dapet:
a=3
b=2
c=-5
Fungsi kuadrat: f(x)=3x^2 + 2x - 5