Question

Cara untuk menyelesaikan soal diatas ?

Answer 1

Verified answer

Bab Limit
Matematika SMA Kelas X

lim (tan² 3x)/(sin² 4x)
x→0 

= 3²/4²
= 9/16

cara panjang
lim (tan 3x . tan 3x) / (sin 4x . sin 4x)
x→0
= lim ((tan 3x)/x) . (tan 3x/x) . (x/sin 4x) . (x/sin 4x)
   x→0
= (3 . 3) / (4 . 4)
= 9/16

Answer 2

Verified answer

Matematika XI SMA
→→ Limit ←←

Pembahasan :
Lim [x » 0] (Tan² 3x)/(Sin² 4x)
Lim [x » 0] [(Tan 3x)/(Sin 4x)]²

Pakai sifat Limit
Lim [x » 0] (Tan ax)/(Sin bx) = a/b

Maka...
Lim [x » 0] [(Tan 3x)/(Sin 4x)]²
= (3/4)²
= 9/16