Question

Mohon bantuannya?????

Answer 1

Verified answer

Answer 2

8 lampu = 2 rusak dan 6 baik

Dibeli 2 lampu :
n(S) = 8C2 = 8!/(8 - 2)!.2! = (8 . 7 . 6!)/(6!. 2 . 1) = 28

Yang terbeli 2 lampu rusak :
n(A) = 2C2 = 1

Peluang : P(A) = n(A)/n(S) = 1/28