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∫(1/(y-1)) dy = ∫(1/x) dx
ln (y-1) + C = ln x + C
2. xy dy/dx = (x²+1)/(y+1)
∫ ((y+1).y) dy = ∫ (x²+1)/x dx
∫ y²+y dy = ∫ x dx + ∫ (1/x) dx
(1/3)y³ + (1/2)y² + C = (1/2)x² + ln x + C