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l₀= 1m
t₁= 20°C
t₂= 220°C
Δt= t₂-t₁
Δt= 200°C
α=0,000012/°C = 1,2×10⁻⁵ /°C
Dit =lt
Jwb=
lt= l₀(1+ α.Δt)
lt= 1(1+ 1,2×10₅⁻⁵.200)
lt= 1(1+ 2,4×10⁻³ )
lt= 1+2,4×10⁻³
lt=1,0024 m