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l₀= 1m
t₁= 20°C
t₂= 220°C
Δt=t₂-t₁
Δt= 200°C
α= 0,000012/°C = 1.2×10⁻⁵/°C
Dit= lt
Jwb=
lt= l₀(1+α.Δt)
lt= 1(1+1,2×10⁻⁵.200)
lt= 1(1+2,4×10⁻³)
lt= 1+2,4×10⁻³
lt=1,0024 m