Buatlah konfigurasi elektron (prinsip aufbau)
1. fe, , no atom = 26
2. Zn, no atom = 30
3. Br, no atom = 35
4. I, no atom = 53
5. Bi, no atom = 85
terimakasih :)
1. fe, , no atom = 26
2. Zn, no atom = 30
3. Br, no atom = 35
4. I, no atom = 53
5. Bi, no atom = 85
terimakasih :)
Risep
Untuk yang nomer 5 nomor atom nya Bismuth (Bi) bukan 85 tapi 83
![_{26}Fe=[Ar]3d^6~4s^2 \\ \\ _{30}Zn=[Ar]3d^{10}~4s^2 \\ \\ _{35}Br=[Ar]3d^{10}~4s^2~4p^5 \\ \\ _{53}I=[Kr]4d^{10}~5s^2~5p^5 \\ \\ _{83}Bi=[Xe]4f^{14}~5d^{10}~6s^2~6p^3](https://tex.z-dn.net/?f=_%7B26%7DFe%3D%5BAr%5D3d%5E6%7E4s%5E2+%5C%5C++%5C%5C+_%7B30%7DZn%3D%5BAr%5D3d%5E%7B10%7D%7E4s%5E2+%5C%5C++%5C%5C+_%7B35%7DBr%3D%5BAr%5D3d%5E%7B10%7D%7E4s%5E2%7E4p%5E5+%5C%5C++%5C%5C+_%7B53%7DI%3D%5BKr%5D4d%5E%7B10%7D%7E5s%5E2%7E5p%5E5+%5C%5C++%5C%5C+_%7B83%7DBi%3D%5BXe%5D4f%5E%7B14%7D%7E5d%5E%7B10%7D%7E6s%5E2%7E6p%5E3 "_{26}Fe=[Ar]3d^6~4s^2 \\ \\ _{30}Zn=[Ar]3d^{10}~4s^2 \\ \\ _{35}Br=[Ar]3d^{10}~4s^2~4p^5 \\ \\ _{53}I=[Kr]4d^{10}~5s^2~5p^5 \\ \\ _{83}Bi=[Xe]4f^{14}~5d^{10}~6s^2~6p^3")
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Thanks 1
asrinsr
Ar, Kr Xe itu apa kak? ga paham
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