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melalui titik=(-1,1)
dit:fungsi kuadrad?
jwb=
y=a(x-xp)²+yp
y=a(x-1)²+5
y=a(x²-2x+1)+5
melalui titik (-1,1), maka
1=a(-1²-2(-1)+1)+5
1-5=4a → a=-1
substitusi a=-1 ke..
y=-1(x²-2x+1)+5
y=-x²+2x-1+5
y=-x²+2x+4
#semoga bermanfaay