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b=25cm
c=28cm
p=½(17+25+28)=35
ze wzoru herona obliczam pole=
P=pierwiastek z : 35(35-17)(35-25)(35-28)=√44100=210cm²
obwód=17+25+28=70cm
promień r=2×210:70=6cm
odp. pole trójkata ma 210cm² , a promień okregu wpisanego=6cm