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d=dł. przekatnej=a√2
a√2=a+2
a√2-a=2
a(√2-1)=2 /: (√2-1)
a= 2/(√2-1)=[2(√2+1)] / [ ( √2-1)(√2+1)]=2√2+2
obwód=4a=4(2√2+2)=8√2+8=8(√2+1) cm