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Cw=380J/kg×⁰C
m=5kg
Δt=30⁰C-20⁰C=10⁰C
ΔEw=Q
Q=cmΔt
Q=380/kg×⁰C x 5kg x 10⁰C=19 000J
ΔEw=19 000J
Odp: Energia wewnętrzna bloku zmieniła się o 19 000J.