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abc = 8000
b = ar
c = ar²
substitusi:
a(ar)(ar²) = 8000
(ar)³ = 8000
ar = 20 = b
a + b + c = 54
a + 20 + c = 54
a + c = 34
a , ar , ar²
hasil kali = (ar)³ = 8000
ar = 20
ar = b
a + b + c = 54
a + c = 54 - 20
a + c = 34