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f(x+1) = 2(x+1)³ - 6(x+1)
f(x+1) = 2(x³ + 3x² + 3x + 1) - 6x - 6
f(x+1) = 2x³ + 6x² + 6x + 2 - 6x - 6
f(x+1) = 2x³ + 6x² - 4
semoga dapat di pahami
f (x+1) = 2 (x+1)³ - 6 (x+1)
= 2 (x³+3x²+3x+1) - 6 (x+1)
= 2x³ + 6x² + 6x + 2 - (6x+6)
= 2x³ + 6x² + 6x + 2 - 6x - 6
= 2x³ + 6x² - 4