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Rumus
OH- = Kb x molaritas basa/molaritas garam
OH- = 10^-5 x 0.1/0.05 = 2 x 10^-5
POH = -log 2 x 10^-5
= 5-log2
PH = 14 - POH
= 9+log2 B
Besok tryout kimia ya?