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36 x 5/9 = 20
20 + 273 = 293 K
2. 525 K = 525 -273 = 252
= 252 x 9/5 + 32
= 485.6 Fahrenheit [°F]
3. 153 K - 273 = -120
= -120 x 9/5 + 32
= -184 Fahrenheit [°F]
(5/9 × (68-32)) + 273
--->293K
2.523K =...F
(9/5 × (523-273)) + 32
-----> 482°F
3.153K=....R
4/5 × (153 + 273)
4/5 × -120
----> -96°R
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