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Q = 0.25 x 4200 (kalor jenis air biasanya 4200) x 80
Q = 84.000 J
T1 = 20 derajat
T2 = 100 derajat
maka , q = m x c x ( t2-t1)
= 0,25 x 4200 x ( 100 - 20)
=1050 x80
= 84000
ketentuan: C air = 4200 joule/kg = 1 kal/gr