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[(√5+x + √5-x)/(√5+x + √5-x)]
= lim ((5 + x) - (5 - x))/x(√5+x + √5-x)
x->0
= lim 2x/x(√5+x + √5-x)
x->0
= lim 2/(√5+x + √5-x)
x->0
= 2/2√5
= 1/√5
= (1/5)√5