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3(2c + 1)(2c - 3) - 5c(2c + 1) =3[ (2c + 1)(2c - 3) ] - 10c² - 5c
= 3[ 4c² - 6c + 2c - 3 ] - 10c² - 5c
= 3(4c² - 4c - 3) - 10c² - 5c
= 12c² - 12c - 12 - 10c² - 5c
= 12c - 10c² - 12c - 5c - 12
= 2c² - 17c - 12
semoga membantu.
=12c^2 - 10c^2 -8c + 6c - 5c - 9
=44c^2 - 7c - 9
=