Bentuk (1 - sin kuadratx) (1 + tan kuadratx) adalah
tolong bantu
tolong bantu
Takamori37
Dengan identitas : sin²x + cos²x = 1
![$\begin{align}(1-\sin^2x)(1+\tan^2x)&=\cos^2x\left[1+\frac{\sin^2x}{\cos^2x}\right]\\&=\cos^2x\left[\frac{\cos^2x+\sin^2x}{\cos^2x}\right] \\ &=\cos^2x\times\frac{1}{\cos^2x} \\ &=1\end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%281-%5Csin%5E2x%29%281%2B%5Ctan%5E2x%29%26%3D%5Ccos%5E2x%5Cleft%5B1%2B%5Cfrac%7B%5Csin%5E2x%7D%7B%5Ccos%5E2x%7D%5Cright%5D%5C%5C%26%3D%5Ccos%5E2x%5Cleft%5B%5Cfrac%7B%5Ccos%5E2x%2B%5Csin%5E2x%7D%7B%5Ccos%5E2x%7D%5Cright%5D+%5C%5C+%26%3D%5Ccos%5E2x%5Ctimes%5Cfrac%7B1%7D%7B%5Ccos%5E2x%7D+%5C%5C+%26%3D1%5Cend%7Balign%7D "$\begin{align}(1-\sin^2x)(1+\tan^2x)&=\cos^2x\left[1+\frac{\sin^2x}{\cos^2x}\right]\\&=\cos^2x\left[\frac{\cos^2x+\sin^2x}{\cos^2x}\right] \\ &=\cos^2x\times\frac{1}{\cos^2x} \\ &=1\end{align}")
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