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m1 = 75 gr = 0,075 kg
m2 = 50 gr 0,05 kg
T1 = 0°C
T2 = 100°C
c = 4200 J/kg°C
Ditanya : Tc ?
Jawab :
Q = m x c x ΔT
Qlepas = Qserap, maka
m2 x c (100 - Tc) = m1 x c (Tc - 0)
m2 (100 - Tc) = m1 (Tc - 0)
0,05 (100 - Tc) = 0,075 (Tc - 0)
5 - 0,05Tc = 0,075Tc - 0
5 + 0 = 0,075Tc + 0,05Tc
5 = 0,125Tc
Tc = 5 / 0,125
Tc = 40°C
Jadi suhu akhir campuran adalah 40°C.
Moga membantu :)
m₁ = 75 g
t₁ = 0'c
m₂ = 50 g
t₂ = 100'c
Dit : suhu campuran (tc)......?
Q terima = Q lepas
m₁ . c . (tc-t₁) = m₂ . c .(t₂-tc)
75 (tc-0) = 50 (100-tc)
75tc = 5000 - 50tc
75tc + 50tc = 5000
125tc = 5000
tc = 5000/125
tc= 40'c
jadi suhu campuran = 40'C