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U3 = a + 2b = 36 - x 2
2a + 10b = 144
2a + 4b = 72 -
6b = 72 ; b=12
a + 2b = 36
a + 2(12) = 36
a + 24 = 36 ; a= 12
U10 = a+9b = 12 + 9(12) = 12 + 108 = 120
36 = a + 2b
u5 + u7 = a + 4b + a + 6b = 144
2a + 10b = 144
a + 5b = 72
eliminasi
a + 2b = 36
a + 5b = 72
_________ _
-3b = -36
b = 12
substitusi
a + 5b = 72
a + 5.12 = 72
a = 72-60 = 12
u10 = a + (n-1)b
= 12 + 9.12
= 12 + 108
= 120