Question

Bardzzo prosze o szybka odpowiedz.

Zad.1

Wartosc liczbowa wyrazenia -(-2ab²+¼a²)² dla a= -4 b=√2 wynosi:

A)400 b) -400 c)144 d)-144

Zad.2

Jednomian przeciwny do uporzadkowanego jednomianu -0,25x²(-3)xy(-1⅓)yy³ ma postac :

A)1-x³ydo potegi piatej (nieumialem zapisac wiec bede pisac tak

B)x²y³ c)-x²y³ d)x³y do potegi piatej

Zad.3

W rombie jedna przekatna ma dlugosc 12 cm druga o x cm krotsza (x<12).Jak zmieni sie polle rombu jesli dluzsza przekatna rombu zmniejszymy o 6 cm

A)zmniejszy sie o 6cm² b)zmniejszy sie o (36-3x)cm² c)zmniejszy sie o 3x cm²

D) trudno powiedziec

Zad.4

Po wylaczeniu wspolnego czynnika przed nawias w wyrazeniu -x²(kreska ulamkowa)na 4 - 2xy² otrzymasz:

D

Answer 1

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                          Rozwiązanie w załączniku