BARDZO PROSZE O POMOC (DAJE 48 PUNKTÓW I NAJJJ) zadanie w załączniku c). i d.).... Question from @27728284

27728284 @27728284

March 2022 2 14 Report

BARDZO PROSZE O POMOC (DAJE 48 PUNKTÓW I NAJJJ) zadanie w załączniku c). i d.)

krystynapasek2

Odpowiedź

e) x= - 3 ; y= 10

x ( 1,2 x -y) + x ( - 4,2 x +y-1)= 1,2 x² - xy - 4,2x²+xy -x= -3x²- (-3)=

=-3 *( -3)²+3= 3*9 +3= 27+3= 30

d) x = - 1 ;y= - 1/3

1 i 1/2x ( 4x-2y -6) - 4x ( 1 i 1/2x-2 i 1/4)=

= 3/2x( 4x-2y -6) -4x( 3/2x-9/4 )= 12/2 x²-3xy-9 x-12/2x²+9x=

=-3xy = -3* (-1) *(-1/3) = 3*(-1/3)=- 3/3= - 1

Szczegółowe wyjaśnienie:

1 votes Thanks 1

Magda

Odpowiedź:

$c)\ \ x(1,2x-y)+x(-4,2x+y-1)=1,2x^2-xy-4,2x^2+xy-x=-3x^2-x\\\\x=-3\ \ ,\ \ y=10\\\\-3x^2-x=-3\cdot(-3)^2-(-3)=-3\cdot9+3=-27+3=-24\\\\\\d)\ \ 1\frac{1}{2}x(4x-2y-6)-4x(1\frac{1}{2}x-2\frac{1}{4})=\frac{3}{2}x(4x-2y-6)-4x(\frac{3}{2}x-\frac{9}{4})=\\\\=6x^2-3xy-9x-6x^2+9x=-3xy\\\\x=-1\ \ ,\ \ y=-\frac{1}{3}\\\\-3xy=-3\cdot(-1)\cdot(-\frac{1}{3})=\not3\cdot(-\frac{1}{\not3})=-1$

2 votes Thanks 1

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