Question

Bardzo proszę o pomoc,zadanie w zakładkach

Answer 1

12.
a) (1/2)^-3 + 1^-3 / 2 = 2^3 + 1^3/2 = 8 + 1/2 = 8 i 1/2
b) 1^-1 + 2^-2 + 2^-3 = 1^1 + (1/2)^2 + (1/2)3 = 1 + 1/4 + 1/8 = 1 1/4 + 1/8 = 1 2/8 + 1/8 = 1 i 3/8
c) 1/2 * 2^-1+4^-2 = 1/2 * 1/2+(1/4)2 = 1/4 + 1/16 = 4/16 + 1/16 = 5/16
d) -(1 1/4)^-1+2^-2+2^-1 = -(4/5)^1 + (1/2)^2 + (1/2)^1 = -4/5 + 1/4 + 1/2 = -8/20+5/20+10/20 = 7/20
e) (1/4)^-1+1/4^-1+4^-1 = 4+1:1/4+1/4=4+1*4+1/4=8 1/4
f) [4^-1-2*(2/3)^-3] = [1/4-2*(3/2)^3]=[1/4-2*(27/8)]=1/4-27/4=-26/4=-6 1/2
g) (-2)^-2+(-1/2)^-2+1/[(-2)^2]+(-1)^-2/2= (-1/2)^2+(-2)^2+1/(-1/2)^2+1/2 = 1/4+4+1:1/4+1/2=1/4+4+1*4+1/2=4 1/4+4+2/4 = 8 3/4

Mam nadzieje, że pomogłam :)