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√(3-2√2)+2-√2 = √(2-2√2 +1)+2-√2 = √(√2-1)²+2-√2 = √2 - 1+2-√2 = 1
2)
√(x+2√(x-1)) - √(x-2√(x-1)) x≥2
x-1 =y
x = y+1
y+1≥2
y≥1
√(y+2√y+1) - √(y-2√y+1) = √(y+1)² + √(1-y)² = y+1 - y+1 = 2