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D = {-2, -1, 0, 1}
f(x) = 3x - 2
Maka,
f(-2) = 3(-2) -2 = -6-2 = -8
f(-1) = 3(-1) -2 = -3-2 = -5
f(0) = 3(0) -2 = 0 - 2 = -2
f(1) = 3(1) -2 = 3 - 2 = 1
Maka, rangenya adalah:
{-8, -5, -2, 1}
Pilihan : [C]
domain = {-2,-1,0,1}
f(-2) = 3(-2)-2 = -6-2 = -8
f(-1) = 3(-1)-2 = -3-2 = -5
f(0) = 3(0)-2 = 0-2 = -2
f(1) = 3(1)-2 = 3-2 = 1
range = {-8,-5,-2,1}