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(2+a+2 -1+0-2)
(1-a 0)
(4+a -3)
determinan (AB) = 6
(-3+3a) - 0 = 6
3a = 9
a=3
mka AB = (-2 0)
(7 -3)
B^-1.A^-1 = (AB)^-1 =
1/6 (-3 0)
(-7 -2)
16. (AB^-1)^-1 = (1 -1)
(3 0)
B.A^-1 = (1 -1)
(3 0)
B = (1 -1) . A
(3 0)
B = (1 -1) (2 3) = (3 2)
(3 0) (-1 1) (6 9)