Integral
koreksi soal
∫(5x + 3) dx [1 a] = 6
5/2 x² + 3x = 6
5/2 (1² - a²) + 3(1 - a) = 6
kedua ruas kalikan 2
5 - 5a² + 6 - 6a = 12
5a² + 6a + 1 = 0
(5a + 1)(a + 1) = 0
a = -1/5 atau a = -1
Nilai a :
-1 atau -1/5
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Verified answer
Integral
koreksi soal
∫(5x + 3) dx [1 a] = 6
∫(5x + 3) dx [1 a] = 6
5/2 x² + 3x = 6
5/2 (1² - a²) + 3(1 - a) = 6
kedua ruas kalikan 2
5 - 5a² + 6 - 6a = 12
5a² + 6a + 1 = 0
(5a + 1)(a + 1) = 0
a = -1/5 atau a = -1
Nilai a :
-1 atau -1/5