Question

Bantu jawab pakai cara dan rumus​ nomor 8 saja​

Answer 1

soal8 :

u = 1 + x²

du = 2x.dx

dx = [tex]\frac{1}{2x}[/tex]du

x² = (u - 1)

x = √(u-1)

x⁴dx = (u-1)²[tex]\frac{1}{2x}du[/tex]

=

[tex](u-1)^2\frac{1}{2\sqrt{u-1}}du[/tex]

= ½[tex](u-1)^{\frac{3}{2}}[/tex]du

[tex]\int{x^4\sqrt{1+x²}}dx = [/tex]

[tex]\int{\sqrt{u}}\frac{1}{2}(u-1)^{\frac{3}{2}}[/tex]du