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1. menggunakan rumus =
= = jadi, pH = 3-log
8. Ca(OH)2 ⇔ Ca⁺ + 2(OH)⁻
4.10^-6 = (4s)³
s =
s = 10^-2
Ca(OH)2 ⇔ Ca⁺ + 2(OH)⁻
Ksp = 10^-2 (10^-2)² <didapatkan dari pH = 12, maka pOH= 2, OH⁻ = 10^-2>
Ksp = 10^-6