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a]
r=6cm
pole koła=πr²=π*6²=36π
pole wycinka=1/6*36π=6π
36π-6π=30πcm² pdp. B
b]
2πr=2π*6=12π
dł. łuku=1/6*12π=2π
szukana odp. =12π-2π=10π
obwód=10π+2r=10π+12
odp. A
3]
a,b=dł. boków
b=75%a=0,75a
2a+2b=49
2a+2*0,75a=49
3,5a=49
a=49/3,5=14dm b=0,75*14=10,5dm
pole=ab=14*10,5=147dm²